Recent content by mfratczak88

did you get (2r1+2r2+R) in the denominator ?

It will be I = E1-E2/(r1+r2+(1/2)R). But this is the current for equivalent resistor. The question was what was the current flowing through each of the resistors. So in this case, if they have the same resistance the current will be half of the value above, which is E1-E2/(2r1+2r2+R)

So what should be the answer then ? I still don't get it why my KVLs is wrong ?

(1/2)(R)

Can you write down KVL ? Whatever I can think of, the my KVL equations seems to be the same.

From KVL, if I go with the direction of the current in the inner loop on the left, with E2 there's a voltage drop as I am going from + to minus, with E1 there's a voltage increase as I am going from - to +. So it should be E1 - E2 not E2 - E1, the rest should be fine.

I've edited my post, because I couldn't post the image. There you will find my solution.

It's ABCD question with answers attached. Problem is that, I don't think that neither of those are correct. From KVL the equation seems to be i = (E2-E1)/(2r1+2r2 + R). I've attached images of the circuit, answers, and my solution. Can someone please point me if I am wrong, and if yes, where's...