I have been working on this for more than a week, and i still have no solution. Also no one seems to be able to help. I'm running out of time and I'm just trying to understand how the kinetic energy of the mass falling is converted into the kinetic energy of the hacky sack with a beam with the...
IS this purely a matter of torques? Torque of gravity on the board, torque of hacky sack on the board, torque required to get the hacky sack to a certain velocity? Then countering all those torques?
Would Torque for velocity be KE = 1/2 (m) v^2 so then W = torque (theta-sweep angle) ?
can't we make a similar assumption if it's a marble (I know that it really isn't the same since the object is rolling, and gravity has an effect on how the ball spins and therefore changes the acceleration). However we never did it this way since it is high school physics after all. So i don't...
I posted on the college forum just to see if we can see what others have to say... if anything lol I have AP test next week, all kinds of things to do for this physics project, this is the most important part at least. THe rest the calculations i'll have to do are all basic, so I'm good. Refresh...
I have a seesaw style catapult.
the arms are at a 4 to 1 ratio. I have all the masses and everything, the hacky is 50 grams, and The beam is 381 grams with a length of 50 cm (1 arm is 40 other is 10).
My velocity to launch the hacky 2.5 meters away from the release point and have it land...
Yeah, I know it won't work with a kg of mass from that small of a height, using my hand, with correct rations and everything, and a lip to keep the hacky sack from releasing early, I still can't get it to go 2.5 m horizontally. The best I can get hitting it very hard is about 1 m.
Should I...
I tried setting something similar to this last night with the wood at the exact length and the ratio's were pretty close. The height of the fulcrum was a little less than it should be but I was just using my hand impacting the wood as the force. I found it EXTREMELY difficult to get much height...
I'll cut the wood tomorrow and set it up and run some experiments to see what happens, and if it's not a whole lot off (meaning i don't have to adjust the drop height more then 3 cm or so, i'll do an error analysis, if not, i may factor it it in. However if i have to adjust by 10 cm + then we...
Are you sure about those numbers? watch the decimal places maybe? Because (11.8 - .98 )(.01) = V doesn't get you that big of a number. I won't take those things into account.