Liquid is flowing into a small tank which has a leak. Initially the tank is empty and, t minutes later, the volume of liquid in the tank is V cm3 . The liquid is flowing into the tank at a constant rate of 80 cm3 per minute. Because of the leak, liquid is being lost from the tank at a rate...
I substituted h=2 and r=1 into V= $\frac{1}{3}$$\pi$${r}^{2}$h and get the original volume which is $\frac{2\pi}{3}$ and using the ans i found to find the height when the volume is one-eighth which i got is 1/4.
I have found dr/dh and dv/dr and substituted h=1/4 in and use them to find dh/dv. Then i multiplied dv/dh with dv/dt but i still cannot get the ans. :(