Thanks SammyS! I got it right this time. I should have known that the angle I was using was the angle measured from the surface rather than the normal but somehow it slipped my mind.
A flashlight on the bottom of a 4.10 m deep swimming pool sends a ray upward and at an angle so that the ray strikes the surface of the water 2.25 m from the point directly above the flashlight. What angle (in air) does the emerging ray make with the water's surface?
I attempted to find the...