Homework Statement
In a pairs skating competition, the male skater is initially carrying his partner. Together they have a mass of 130.0 kg and they are are moving forward with a velocity of 2.5 m/s. If the male skater throws his partner forward at 1.5m/s, find the velocity of the male skater...
But ... If the second ball at rest has a momentum of 0kg°m/s ... Then M(a)3.5m/s (a)= 5.0kg(b)0m/s(b)
So saying (?)*(3.5m/s) + (5.0kg)*( 0 m/s) = 2.5 m/s..
Homework Statement
A ball rolls at a velocity of 3.5m/s toward a 5.0kg ball at rest. They collide and stick and move off at 2.5 m/s. What was the mass of the moving ball?[/B]Homework Equations
Pa + Pb = 0
M(a)V(a) = - M(b)V(b)[/B]The Attempt at a Solution
So.. The ball at rest had zero...
Fnet = 1.25 x 1.4 = 1.75 net force hahahah I get it... Is it not 24N + 1.75N = 25.75= only 2 SIG figs so 2.6 x 101N = the force Gareth exerts on the rope
I'm just confused with the weight of the rope... Cause isn't it possible that there is gravity beeing exerted onto it... And wouldn't that have an impact on the result
Well I know u guys are just here to help people and share the beauty of physics.. But for some reason... Me and physics don't click.. And I just spent 4h doing 5 questions 2 ,of which I never completed .. These questions are Newtons 2nd law. I think I just wasted 4h of my life. Didnt even figure...
Homework Statement
Problem in photo...
Homework Equations
Don't know... Cause velocity ( m/s) isn't acceleration and therefore you can't find Fnet... So I don't know
The Attempt at a Solution
Does it have anything to do with finding Fn than multiplying that?