Yea I actually have that formula. So would I find the force of friction for the wet pavement and then the force of friction for the dry pavement? Then how would I incorporate those answers into finding the stopping distance?
sorry about that i don't really know how to get around on this site really. So far i know that the given coefficiants of kinetic friction for rubber on dry concrete is 0.85 and for rubber on wet concrete is 0.60. I know you somehow have to add all the forces in the problem using F=(m)(g) and...
A 1500-kilogram automobile travels at a speed of 90 km/h along a straight concrete highway. Faced with an emergency situation, the driver jams on the brakes , and the car skids to a stop. What will the stopping distance be for (a) dry pavement and (b) wet pavement?
A 3.0-kilogram object initially at rest explodes and splits into three fragments. One fragment has a mass of 0.50 kg and flies off along the negative x-axis at a speed of 2.8 m/s, and another has a mass of 1.3 kg and flies off along the negative y-axis at a speed of 1.5 m/s. What are the speed...