That's exactly what i was looking for! Thank you!
I solved it without zener, but used diode and a voltage source instead, hopefully it's correct!
Thanks again!
i want to design a diode circuit where the Vo vs. Vi looks like this:
Vi between -2 and 2 Vo = Vi
Vi between 2 and 4 Vo is a linear with slope 0.5
Vi between -2 and -4 Vo is a linear with slope 0.5
Vi>4 Vo=3
Vi<4 Vo=-3
how can i do this?
Well the problem is not about this sum, if you find a series like the one described the problem will be solved.
i have submitted the following answer:
2+4+8+16+32+64+...+2^k = 2(1+2+4+8+...+2^(k-1) = 2(2^k -1)/2-1 = 2(2^k -1)
but 2^k = n
k = log (base 2) n right, then substitute in the...
yeah, i should've added more restrictions.
well the numbers must increase as we go on, for example:
1+2+3+...+n=n(n+1)/2 right, but this is of second order
i want to add numbers that increase up to n, and their sum is of order 1.
i need to find a series of numbers up to n that will add up to kn
x1 + x2 + x3+ ... + n = kn
where k is a constant.
this is part of a long complex problem once this sum is found it will finally be solved.
hello,
i designed a project and i finished it my final step is i want the user to enter 3 bits
if it was 000 i will do the first choice, which has 4 inputs and 14 outputs displayed on the 2 digit 7 segment dispaly
if it was 001 i will do the second choice, which has 5 inputs and 7 outputs...
i'm trying to solve the problem by finding the integral factor by inspection:
1) y(2 - 3xy)dx - xdy =0
2) y(x^2+y^2-1)dx + x(x^2+y^2+1)dy=0
i can't solve those two questions! Help please.
Thanks in advance
Thanks, but what is its value?
is it V=Kq\r1 through r1<r<r2 or is it V=kq/r2
because if i considered the potential being the integral from a to b for E.dl where b is at infinity so Vb wil be zero then i will get Va:
a) at distance r1 it will be Kq/r1
b) at distance r2 it will be k(q+Q)/r2...
Homework Statement
its not a statement but i was wondering: I'm studying the electric potential and when we have a sphere with inner radious r1 and outer radious r2 that has a charge let's say +Q with a cavity and there is a point charge q inside this cavity so the inner surface will have -q...