^
i had it that way the first time. i think i changed it because i got
3 log x = log 27
then to solve for x i got something that looks like this:
x = log 27/3 log
3 log? is it supposed to be 3 log 1?
if so, the answer is 0. i put 0 on my exam, although i set it up incorrectly...
ah^
that is like the other question i posted. I forgot on the exam that addition is multiplication. Well, not on the expanding log questions but on solve for x questions.
Homework Statement
log x2 + log x - log 2.7 = log 10
solve for x
Homework Equations
The Attempt at a Solution
this one i really don't know how to do. I can't find any examples, but this is what i tried (youre going to be like, what? but i had to attempt it.) I think when logs...
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well, that would make it easier, now wouldn't it? prob why i got it wrong on the exam. i totally forgot about that.
To get 5, I divided
(log 8 + log 4)/(log 8 - log 4)
which is
1.505149978/.3010299957 = 4.999999998
thank you though for reminding me about the bases. I couldn't do it...
Just wondering if someone can tell me if I got this correct. It was a problem on my midterm a month ago and I am going over the probs I got wrong, and I don't know the correct answers.
Homework Statement
4(x+1)= 8(x-1)
Homework Equations
The Attempt at a Solution
log 4(x+1) =...
One more question about even and odd trig functions. would a graph of a function that is symmetrical about the y-axis be even and one symmetric about the x-axis be odd?
thank you both so much. as for the cos(sin(-x)) , i meant to say the cos of the negative sin would be even due to the cos, but i completely left out the sin on that one.
and thanks for the explanations. even though i already understood even and odd functions, bringing sin and cos into them...
Homework Statement
I don't know how other people learned trig, but in my book, the first 2 chapters have nothing to do with angles, but are mostly circles and trig functions of real numbers. Does this make sense to anyone? I am in the next chapter already and I know there are other, easier...
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yes, when i did a search, a post with the same link came up. i bookmarked that site for future reference, but its still 2 sections ahead of what i am doing right now. i had a feeling the post might be confusing, as i couldn't find any information on it on the internet, so that must mean...
Homework Statement
This isn't exactly a problem. Also, it is only the first section of the chapter on trig, and this has nothing to do with trig, per se. I think it is more of like a primer for what is to come. So, whomever reads this, please try to imagine you know nothing about sin...
youre right about the thinking hurting. sometimes i feel like my brain is at terminal capacity, but i hate having these open questions.
ive figured out, albeit backwards, that 1/4 is 2-2 so
23x=2-2
base 2 cancels leaving 3x=-2 and algebra = 8-2/3=1/4. it seems so obvious, and i did...
ok, so if i do, for example,
i feel i am still in the same predicament of not knowing how to find out what the exponent (to any base i choose) would be (meaning 3x=\sqrt{27}, how would i figure out the x).
eg., if i were to use base 3 for both, log33 is 1 but i still am left with...
Homework Statement
Im not looking for answers as i know the answers already. i also know that given time and a calculator, i could figure these out, but i have neither for the exams. I am just wondering the general way of setting problems like this up, so i can solve others in the future...
well, on the area equation, i did write it wrong, it was supposed to be:
A = 15x - 1/2x2 - 1/8\Pix2
anyway, there are 2 x2, so i don't know. i can only see there being one maximum. i don't know, maybe its because the pi is in there and there are 2 numbers of the same degree, i just don't...