So I'm aware that uranium 235 is the fissile isotope which is used in fuel for most reactors (about 3% of all uranium fuel for example), but what actually happens to the other 97% of the U-238 if it doesn't undergo fission?
I get some of it absorbs neutrons making it U-239? But I've also seen...
Thanks all that's clarified it for me now. I was getting a bit confused.
However just one more query, how does CS-137 (as an example) give off beta/gamma radiation within the 30 year period if it is not 'decaying' until it hits that 30 years time? Or am I misunderstanding something trivial...
As I understand, half life's are where unstable nuclear isotopes Undergo radioactive decay, where they emmit either aplha beta or gamma during this decay.
I'm looking for some clarification on whether when an atom undergoes decay, does it then change into another element/ isotope of an...
Thanks for the replies and guidance, really appreciated.
I am still struggling to clarify how to calculate the forces on the head though. If I were to use a collet or similar and lift from under the head, is the stress simply F/A? And is it purely compression on the under side?
Many thanks
Thanks for the reply
It will be steel, and I'm planning to use a system that goes around the disc/ flared head and clamps underneath (lifting from the underside of the disc) and lifts up from there. I'm aiming to make it something that connects to a crane or similar system so it's hoisted up...
I'm designing a lifting tool for a bar with a flared head. The bar is say 10m long and 10mm in diameter with a head on the top that is 20mm in diameter and 10mm thick. There is a fillet from the head to the bar of 2mm (for reducing stress concentrations).
The bar will be lifted vertically and...
Thanks for your help so far.
Sorry, i understand i missed out the horizontal and vertical components.
So if the launch velocity is 50m/s, then the horizontal velocity is
Uh = 50 x cos(50) = 32.13 m/s
The only information I've been given is that there is no air resistance, the ground is...
Sorry, I realized i gave a bit of a poor explanation.
Essentially the horizontal rebound velocity is the same as before the collision. So (-) 50m/s.
There are no lossess due to the collison or air resistance and the ground is level.
My attempts involved using suvat equations to determine the rebound distance :
S = 0.5 * (u + v)*t
With u being 50 and v being 0
t being time taken to fall down (Height of impact / gravitational acceleration)
t = 48.41 / 9.81
Plugging the numbers in gives
S = 123.365m
This is where i get...