The model shown in the figure is extruded 11 meters in the z-direction. In perspective, the height of the beam in y-direction is approximately 220 mm. So it is very long compared to the cross-section. I think I might have been a little unclear in the problem desciption. I want to analyse the...
Both figures are captured from the front plane, but shows the cross-section of the model. The x and y-axis is shown in both figures, and y is in vertical direction. The loading is applied in negative y-direction.
I have the 3D model, and can extract all information from SolidWorks, but these...
Hello.
I am currently working with a beam with the following cross-section:
It consist of three bended sections with the following parameters, alpha = 90 degrees, Thickness = 4 mm, Radius = 50.59 mm.
The top section consist of a small triangle and a rectangle. the triangle have a width = 4 mm...
So neither the static friction nor the kinetic friction have an impact that works as a counterveiling force? This means that only the rolling resistance is working against the acceleration on the wheels? In my case the rolling friction is very small and almost neglitiable. This means that only...
I am currently working on designing a drive system for a vehicle, and I am calulating the necessary torque to accelerate a vehicle. I am using the guidelines of this source:
http://www2.mae.ufl.edu/designlab/motors/EML2322L%20Drive%20Wheel%20Motor%20Torque%20Calculations.pdf
I still feel that...
Fnet is the total external longitudinal force. It includes the needed traction force (m*a = 5*9 = 45 N ) from the wheels, and I also need to compensate for the counterforces in the other direction to still achieve the acceleration of 9 m/s2.
In my understanding, torque and force goes hand in...
I think you are mixing up Fnet and Ft. Ft = ma = 5*9 = 45 N. From this we also need to include the drag force due to air resistance which is given by Fd = 1/2*p*v2*Cd*A and rolling resistance F = Crr*N. Then all the forces is summed together to get Fnet. But these forces are not the problem. I'm...
Im sorry for the limited explanation. I used the different equation for drag force, rolling force and F = ma for the traction force. The reason why I didnt't explain it more thouroughly is that it is a lot of parameters and coefficients. This is not really the part I am questioning. What I want...
<Moved from a technical forum. Therefore no template.>I am currently analysing the forces acting on a moving vehicle. The vehicle is mounted on a rail with wheels on both upper and lower side of the rail with a spring increasing the reaction force, and thereby the friction. The vehicle should be...