This is operating in a frictionless environment. Each bar is the same mass, and like I said there are four making a complete cross. I am trying to see if the whole thing will start rotating about the center as the "south pole" is attracted to the "north pole".
It is my understanding (and it has been awhile since magnetics in college) that it would rotate toward "north" - like a compass. But for sure I would like to be able to control the direction of rotation...
If I have a magnetic setup in frictionless, etc. area as follows:
N
/
/
/
---------------------S
Will the "south" pole rotate up to the "north" pole, causing the system as a whole to rotate?
I was just hoping to verify that my understanding of the conservation of angular momentum does apply to this situation. I seem to have gotten that verification. I appreciate all of the help, and I am sorry for the amount of time it took me to adequately explain the problem.
Thank you to...
Because the bar has no mass, the system will rotate about the 10 kg mass at the end. This mass is shifting from one end to the other, and - according to my understanding of the conservation of angular momentum - the bar will continue to rotate about that 10 kg mass and move from left to right...
The four points are correct, yes. But the mass shifts from one end of the bar to the other as the bar rotates. The bar starts in the position A-B and the mass is at B. Then the bar rotates to B-A and the mass is at A.
Clicking "image" gives me a box to put in a URL, not to upload from my computer. Please try this link:
https://drive.google.com/file/d/0BzHtKK_R-w33M25LUVNGcnkyX2M/view?usp=sharing
"X" is the center of the bar, which is what I would like to plot the position of. The bar pivots about the...
So the rotation of the bar will allow down as the mass is forced from on end to the other? I was hoping to ultimately have some help in deriving an equation for the center of the bar (X) as the bar moves along (as depicted by the second image).
Just to finalize and make sure I understand:
If there are no external forces acting on the bar, except the initial force which begins the rotation about the center of mass - at the 10 kg mass on the end - and the bar is free to rotate about that center of mass, if the center of mass is...
The bar is rotating about the center of mass, which is the 1 kg mass on the end. That mass moves from one end of the bar to the other in the same amount of time it takes the bar to rotate 180 degrees (pi rad). The "X" on the bar is just the center of the bar, which is what i want to plot the...
Here is an image which goes along with my descriptions. Points A and B alternate in position as the mass shifts from end to end of the bar. I am looking to plot the position of point X, the center of the bar.
https://drive.google.com/file/d/0BzHtKK_R-w33TTljSlNoeEZlTDQ/view?usp=sharing
That is the concept, but I am looking for how much power to apply, the magnetic field generated, and the total force exerted on the body moving through the tube. I believe there is some set of governing equations that I can use to describe the system, I just have not been able to find them. I...
I cannot figure out how to insert an image from my computer.
The bar is 1 m with negligible mass. Attached to one end of the bar is a mass of 1 kg. A force of 1 N is applied to the end of the bar opposite the mass. As the bar rotates due to the moment (1 N-m), the mass moves from one end of the...