Recent content by Physics345

I have made my final edits, it looks To describe entropy, let’s begin by discussing what a system is. We can describe a system as any mass which comprises molecules. A room, moon, planet, sun, galaxy, and the universe are all systems. To visually describe entropy one can close their eyes and...

Hello everyone, I made some changes they are as follows: To describe entropy, let’s begin by discussing what a system is. We can describe a system as any mass which comprises molecules. A room, moon, planet, sun, galaxy, and the universe are all systems. To visually describe entropy one can...

Oops, I just realized there is a third law that describes the absolute minimum temperature that I related to the zeroth law. Wait, that's odd does that mean the zeroth law allowed physicists to realize the third Law or did I misunderstand the zeroth law?

Hello everyone, I have to write a paper about entropy and how it relates to the laws of thermodynamics, energy, and work. I have taken a deductive approach starting from the zero-th law to the second law of thermodynamics as follows. Entropy is the disorder of a system (Class Video, 2019)...

I found the height, and its 0.05m

Given: ##y_{2} - y_{1}= 0.2m## ##Q= 1.5\frac{m^{3}}{min}## ##Q= 0.025\frac{m^{3}}{s}## After conversion ##D_{1}= 0.2m## After conversion ##D_{2}= 0.1m## After conversion ##r_{1}= 0.1m## ##r_{2}= 0.05m## ##p_{1} - p_{2} = \frac{1}{2}P(v_{2}^{2}-v_{1}^{2}) + Pg(y_{2}-y_{1})## Calculating...

Either way, the concept was simple. I will come back again when I'm confused. Thanks, Everyone & Best Wishes, Physics345

Another typo. I wish I saw your message earlier. I had my exam today and did not substitute the values.

Oh, I just realized that. I must have added it as I was applying the latex.

Done thanks a lot.

Thanks, I have bookmarked it. Give me a moment to apply the latex.

Solution: ##\frac{\partial z}{\partial x} = yx^{y -1}+1## ##\frac{\partial z}{\partial t} =\frac{\partial z}{\partial x}\frac{\partial x}{\partial t}+\frac{\partial z}{\partial y}\frac{\partial y}{\partial t}## ##\frac{\partial z}{\partial t} = (\frac{yx^{y-1} + 1}{2\sqrt{s+t}}) +...

xy*e^x + ye^x + xe^x * dy/dx + y^2 * e^x + 2ye^x * dy/dx = 0 divide by e^x xy + y + x * dy/dx + y^2 + 2y * dy/dx = 0 y(y+x+1)dx + (x+2y)dy = 0 Genius! You're a lifesaver, thanks.

dM/dY = x+2y+1 dN/dx = 1 (My-Nx)/n = 1 Integrating Factor => e^∫1dx= e^x (xye^x+ye^x+ye^x)dx + (xe^x+2ye^x)dy = 0 dM/dY =xye^x+e^x+2ye^x dN/dx = xye^x+e^x+2ye^x Exact ∫dF/dy * dy = ∫ (xe^x+2ye^x)dy F = xy*e^x + y^2*e^x + c(x) dF/dx = xy*e^x + y*e^x + y^2 * e^x + c'(x)...

What exactly am I not understanding here? Also is there any thing I should relearn to understand this better?