Recent content by Physics_Boi

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    Troubleshooting Spring and Masses: How to Solve for Maximum Compression?

    Ok thank you for the help! I solved the problem successfully using the conservation of momentum and energy!
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    Troubleshooting Spring and Masses: How to Solve for Maximum Compression?

    Momentum would be conserved since there wouldn't be any external force acting on the object.
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    Troubleshooting Spring and Masses: How to Solve for Maximum Compression?

    Oh could I also use conservation of momentum? Does that mean the second block would also have some velocity when the spring is compressed?
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    Troubleshooting Spring and Masses: How to Solve for Maximum Compression?

    1. Homework Statement Attached in the picture below.Homework Equations Spring energy = 0.5Kx2 Kinetic energy = 0.5mv2 The Attempt at a Solution I tried setting the equations for spring energy and kinetic energy equal, since I thought the maximum compression would occur when the box had no...
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    Problem w/ Gravitation, Orbits

    Ok thank you for the help! I plugged in the values into the equation, and solved. I got the correct answer.
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    Problem w/ Gravitation, Orbits

    Ok I will try it and let you know. Thank you for the help!
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    Problem w/ Gravitation, Orbits

    What I did was that I considered the top angle of the triangle. Theta = arctan (a/0.75a) = 53.1 degrees. Then, the remaining two angles must add up to 180 - 53.1 = 126.9 degrees. Since they are the same, 126.9/2 = 63.4 degrees. Am I doing something wrong?
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    Problem w/ Gravitation, Orbits

    That was the conjugate angle. The angle in the triangle I got was a little more than 50 degrees. I then used the fact that the other two angles were equal, and that all the angles added up to 180 degrees (since they form a line) to get the angle of 63.5 degrees.
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    Problem w/ Gravitation, Orbits

    Yes, I used the relationship a^2 - b^2 = c^2 for an ellipse, where a is semi major axis length, b is semi minor axis length, and c is focal length. I knew a and c, so I substituted and just solved for b^2. Using the Latus Rectum properties, b^2/a is the y-coordinate.
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    Problem w/ Gravitation, Orbits

    I found the angle of the velocity to be 63.5 degrees, but when I solved using angular momentum I got a different answer. What I did to find the angle was set up the right triangle (between the two foci and the point), and use inverse tangent to find one of the angles, and use basic addition and...
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    Problem w/ Gravitation, Orbits

    I am preparing for the U.S. Physics Olympiad exam currently. This is one of the problems from the F=ma exam, which is the preliminary test for USPHAO. https://www.aapt.org/physicsteam/2018/
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    Problem w/ Gravitation, Orbits

    I looked at the picture and the distances, but I don’t understand how I would be able to calculate the value of the angle.
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    Problem w/ Gravitation, Orbits

    As for finding the angle theta, wouldn’t that always be 90 degrees because the velocity is tangent to the ellipse? Also, I am not familiar with eccentricity or perihelion radius, so would there be any way to solve this?
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    Problem w/ Gravitation, Orbits

    Then what concepts would I have to use? Is there any specific idea that would be useful?
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    Problem w/ Gravitation, Orbits

    I thought that V was inversely proportional to time. This led me to substitute (1/V) as T into Kepler’s Law.
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