Recent content by Pmand92

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    Traffic Shockwave Physics Topic

    How I figured out Part B: Since I found d to be 60 m, the total distance was 75.0 meter. Part B wanted to know what the speed was when the separation was twice the amount. I multiplied 75.0 m*2 to get 150 meters. I then took the double separation distance and divided by the original velocity...
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    Traffic Shockwave Physics Topic

    Never mind, I figured it out.
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    Traffic Shockwave Physics Topic

    Ok, so I found someone else's thread about this similar problem for part B, but I cannot seem to follow their equation fully: "vsw = (qb – qa)/(kb – ka) Where vsw = propagation velocity of shock wave (m/s) qb = flow prior to change in conditions (vehicles/s) qa = flow after change in conditions...
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    Traffic Shockwave Physics Topic

    Here is the part A answer: Incoming flux = outgoing flux (1/(d + 15.0 m))(26.0 m/s) = (1/15.0 m)(5.20 m/s) d = 60.0 m
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    Traffic Shockwave Physics Topic

    Where are you getting 5.2 m? In the problem, its 5.20 m/s, a velocity. The only distance given in meter is for the buffer zone of 15.0 m.
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    Traffic Shockwave Physics Topic

    I am not sure what you are asking...there is no time interval given in the problem.
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    Traffic Shockwave Physics Topic

    I also forgot to mention on Part A, I tried to follow the YahooAnswers reply using their method, with my variables (it didn't work either): "Since the slow zone is moving at 5m/s, if the shock front is to remain stationary, then there must be 5m/s of cars being added to it. Each car will add...
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    Traffic Shockwave Physics Topic

    1. Homework Statement : An abrupt slowdown in concentrated traffic can travel as a pulse, termed a shock wave, along the line of cars, either downstream (in the traffic direction) or upstream, or it can be stationary. figure below shows a uniformly spaced line of cars moving at speed v = 26.0...
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    Position and Displacement Vectors- The Watermelon Seed Vector

    I am having a hard time visualizing that.
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    Position and Displacement Vectors- The Watermelon Seed Vector

    To be honest, I can't remember all of the ways to find the angle.
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    Position and Displacement Vectors- The Watermelon Seed Vector

    Well I tried using the magnitude (14.8 squared) minus 2.2 squared to find a component so I could try the inverse tangent to find the angle. tan^-1(2.2/14.8)=8.5 degrees and then I subtract that from 180, which 171.5. Then at this point, I tried to put it into WileyPlus, which was wrong. So I...
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    Position and Displacement Vectors- The Watermelon Seed Vector

    I know, it's -2.2m. I forgot to mention it.
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    Position and Displacement Vectors- The Watermelon Seed Vector

    A watermelon seed has the following coordinates: x = -6.6 m, y = 2.2 m, and z = 0 m. Find its position vector as (a) a magnitude and (b) an angle relative to the positive direction of the x axis. If the seed is moved to the xyz coordinates (8.2 m, 0 m, 0 m), what is its displacement as (c) a...
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