A ball bearing is dropped from rest and falls at speed v just before hitting a spring. The spring compresses by a distance of y, and all energy is converted into elastic potential energy in the spring. We are supposed to find F exerted by spring.
The conversion of energy, according to me, is...
Hi Tiny-Tim =),
How do you get a = -kx - mg ?
What is actually the loophole in my reasoning:
Quoted: "Since energy is conserved, I have to assume that the extension (actually compression) at the top is less than extension at bottom as there is also GPE also at the top."
At the top...
If I have a spring with a load and I oscillate it freely, applying hooke's law,
TOP: GPE+EPE(Given by area under F-x graph)
Equilibrium:KE (No EPE since x=0)
Bottom:EPE Only
Since energy is conserved, I have to assume that the extension (actually compression) at the top is less than...
I always thought antinodes were the areas of greatest pressure change as they shift to and fro, reaching maximum amplitudes at both sides. However, one of the questions asked me and the answer says that nodes are the areas of greatest pressure change.
Can anyone help? I am confused with this...
I don't think I am involved with physics calculus at my level. Yes, I do mean that acceleration is less.
My line of reasoning: Same distance vertically->Smaller acceleration (due to air resistance opposing the gravitation [compare with upwards])->Longer time in air (looking at vertical...
^^Without air resistance, I guess symmetrical.
With air resistance, both are not. But where is the peak?
I thought on the way down, resultant force/acceleration is less resulting in a gentler slope, but apparently the answer decides otherwise.
2 URGENT questions on Wave Phase Differences [Diagram Included]!
Two microwave sources S( and S, are situated as shown in Fig. 5.1. The waves emitted by the two sources are in phase and are polarised in the same plane.
http://img190.imageshack.us/img190/3924/wave1f.jpg
A microwave...