r = 1.21x10-4 /year
If I have N C-14 atoms, then 0.7 of those N atoms decay each minute.. 0.7 decay/minute = 367920 atom decays per year.
I'm not sure how it's related to the decay rate. Sorry, I haven't done a problem with two rates before and it's really confusing.
Homework Statement
Suppose you have a 1.4g sample of old charcoal. It produces 0.7 beta decays per minute. How old is the charcoal.
Given:
1g of carbon current day has 6.36x1010 atoms of 14C
Homework Equations
N = Noe-rt
N = number of atoms in the sample (current-day)
No =...
Oh right, I forgot.
After normalization, |\psi> = 1/\sqrt{2}(|\uparrow\downarrow> - |\downarrow\uparrow>) +1/\sqrt{2}(|\uparrow\downarrow> + |\downarrow\uparrow>)
leaving the probability to be in the triplet state (S=1) to be 1/2.
Thanks for your help! I think I got it!
Hello =)
so the singlet state is
|\psi_{singlet}>= 1/(√2)(|\uparrow\downarrow> - |\downarrow\uparrow>)
and the triplet state is
|\psi_{triplet}>= 1/(√2)(|\uparrow\downarrow> + |\downarrow\uparrow>)
so,
|\psi> = 1/2(|\psi_{singlet}> + |\psi_{triplet}>)
in order to get S=1...
Homework Statement
Two particles with spin 1/2 and are in the spin state:
|\psi> = |\uparrow_{1}>|\downarrow_{2}>
where |\uparrow_{1}> is a state where particle 1 has spin up along the z-axis and
|\downarrow_{2}> is a state where particle 2 is spin down along the z-axis.
If...
Ah! yes! I completely forgot about that.
H = (a^{\dagger}a + 1/2)\hbar \omega
I know what to do now. I compute the commutator using Z, and the U's will go away because they commute with H.
Thank you!
in the end I got that Z(t) = Z because
dz(t)/dt = 0 which means that z(t) =...
Homework Statement
A particle of mass m is in a harmonic oscillator potential with spring constant k. An observable quantity is given in the Schrodinger picture by the operator:
Z = a^{\dagger}a a^{\dagger} a
a) Determine the equation of motion of the operator in the Heisenberg...