Recent content by Richard_Steele

  1. R

    B What exactly is an 'exhaustive event'?

    Thanks very much for the answer. The first descriptions about exhaustive events were a little bit confused, but now thanks to your explanation I better understand the concept. Thank you very much!
  2. R

    B What exactly is an 'exhaustive event'?

    Summary: Want to know exactly what an exhaustive event is. A little bit confused about "one of them will occur during the conduct of an experiment". Hi there, I open this thread because I am a little bit confused about what an 'exhaustive event' is. I have been reading some websites and...
  3. R

    How to calculate all the possible combinations....?

    How many choices for the object to go in the first position? 2 choices? 123 132 213 231 312 321 Having made that choice, how many objects do you have left to choose from for the second position? 2 also?
  4. R

    How to calculate all the possible combinations....?

    EDIT: you're asking me about the formula to order n objets. I'm not familiar with it. I would say you that it's possible to get the result (6 possible combinations) using the permutation formula: Right?
  5. R

    How to calculate all the possible combinations....?

    Well, if we have 3 numbers... (call them 1, 2 and 3) We have the following combinations: 123 132 213 231 312 321 Correct?
  6. R

    How to calculate all the possible combinations....?

    I would say that if we have 2 candles and there are 2 possible solutions, then if we have N candles, we will have N possible solutions. Right? For example, if we have 4 candles, we will have 4 possible solutions?
  7. R

    How to calculate all the possible combinations....?

    Sorry, maybe 2? X1 > X2 or X1 < X2 Now better?
  8. R

    How to calculate all the possible combinations....?

    Well, assume that N = 2 , so I have 2 candles. The first and the second candle. Of course, I assume that they can be > or < (not equal). So the solution could be: 16? I don't get the idea.
  9. R

    How to calculate all the possible combinations....?

    I have made the following observations. Check them and say me if I'm right or not. I have 2 candles, the first has the index #1, and the second has the index #2.I assume that if I want to calculate all the possible relations that can exist between each component of the first candle, with each...
  10. R

    How to calculate all the possible combinations....?

    Hello, I have a set of N candles. The candles are vertical and each candle has 4 variables (maximum, minimum, open and close). Each candle can be equal or different length (usually they are different length). For any given candle 4 instead of 2, parameters are used to describe i: max, min, open...
  11. R

    How to calculate all the possible combinations....?

    Homework Statement Hello, I have to solve a problem to calculate all the possible combinations in a dataset. I have candles and each one has 4 values: open, close, high and low. And I have a high number of candles (hundreds). I want to know all the possible scenarios that it's possible to...
  12. R

    How to interpret Cost Function?

    I am going to Google them. It will take time.
  13. R

    How to interpret Cost Function?

    Of course, I understand. I have read something about the 'absolute value', so I previously thought about that the order in the substraction doesn't matter (as you explain in your post). And I better understand why it's not really important to use ##Y_predicted - Y_real## or ##Y_real -...
  14. R

    How to interpret Cost Function?

    Lets start with... How a single error is measured? I think it is: Y value from real - Y value from prediction. This gives you a number that is the error, right?
  15. R

    How to interpret Cost Function?

    Ray Vickson So let's start little by little... let's talk about the first paragraph. Lets think we have a dataset ##(X_1,Y_1), \ldots, (X_n, Y_n)##. As you said, it is possible that those points in the xy space form groups. So our task is to find a straight line that is like the 'mean' of those...
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