Recent content by sankalpmittal

Thank you both for your replies...

So should I opt for computer science? I mean its not only about programming right? I do understand syntax etc of a given programming language. Only problem is application which I often faced as a student of science. I find myself stuck at many programs and others were adept at making them. Also...

I would very much appreciate if you could shed some of your insight on the following question that has been troubling me. I faced difficulty in computer programming as many times I could not find logic for even a simple problem (which many other classmates would do easily) while in some cases I...

Ahh yes thanks. Now I have only one query to clear : Thanks brage. But... I still need some clarity regarding this point.

Thanks for all the replies! I think that I am starting to get it. I just need to clarify the following two points : 1. I have read in textbook that moment of inertia only depends upon "mass distribution" in the body, it has nothing to do with motion of the rigid body. If moment of inertia in...

Thanks. But can you please explain it mathematically. Angular frequency of a physical pendulum is inversely proportional to square root of moment of inertia of system about pivot, other factors being same. So case A and B should have different moment of inertia if their angular frequency is...

Homework Statement A metal rod of length 'L' and mass 'm' is pivoted at one end. A thin disk of mass 'M' and radius 'R' (<L) is attached at its centre to the free end of the rod. Consider two ways the disc is attached : Case A: The disc is not free to rotate about its centre of mass, the...

Thanks! :)

Oh the difference is 2x ?Then if i replace x with 2x in my work will it be correct i think ? Edit: I just did the calculation of my work by replacing x with 2x and got the correct answer as x=6 ! Thanks ehild! But can you please think of any other way without setting up an integral ? I think...

Errm I denote x as the height ascended by mercury on the left side of the tube as the gas does work on it. So I divide the process in three parts : Part I: Right side gets empty.. Work done = ∫(Po+xρHgg)σdx from 0 to l/2 Then after this the pressure is Po+lρHgg/2 Part II : Horizontal side...

I think you're right. So finally by pascal's law the pressure of the gas should be Po + lρHgg... But pressure is varied in the process in turn. So I'll have to set up an integral : Pressure of gas as a function of height x P(x) and integrate it as ∫PdV... to obtain work... So work should be...

Hi ehild! Here's the set up : http://postimg.org/image/6cvxwzubb/4640a742/ Dimensions of xPoρl are in joules. So dimensions of x which we have to find should be [Joules]/Poρl. Now please see the figure. See the dotted datum there. By pascals law pressure in the same liquid at same level...

Coming back after a long time. I would suggest you rather graph y=x^3-6x^2+11x-6 and y=-a on the paper. You can graph the cubic easily by checking at x=0 or may be y=0 and also checking maxima, minima , inflexion point etc. Then plot on the same paper y=-a. Check what values can you give a by...

Homework Statement A thin U-tube with cross sectional areas sealed at one end and open to atmosphere at the other end consists of two bends of length l=250 mm each, forming right angles. The vertical parts of the tube are filled with mercury to half the height that is l/2 on both sides of the...

Yep. Thanks! The second method is shorter! :)