Not following? If a force exerted by the sled onto the side of the course is Fab, then the force back from the side of the course would be -Fba.
I was asking for help how to approach this problem, so if you or someone else would actually care to explain how to solve it that would be helpful.
Again, I already stated earlier in my attempted solution that I was unsure about what value I should use for v in the mf and mi calculations. I could not tell by the diagram which ratio of the angle to use for velocity.
Well the force is delta p/ delta t... so I need the time and the change in momentum. I can find the time (I believe) from the distance of the collision, but the part I'm having trouble with is how to even calculate the impulse of the collision.
I attempted to do mvf-mvi to find the impulse, but had trouble figuring out what to use as v (where does the angle of 3degrees come in?), and thought that there had to be more to the problem considering the other details I was given. I then attempted to maybe calculate the kinetic energy lost...
Hi! I can't solve this. Please someone give me a hint and help? I'm unsure what equation to use. Thank you!🙏🙏🙏
An artillery crew demonstrates its skill by firing a shell at an angle of 49 deg and then lowering the gun barrel and firing a second shell at a smaller angle of 20 deg in such a way...
The answer was revealed to be 30 minutes after turning around- but I'm having trouble understanding why. Can someone please explain this to me? Does it have something to do with relativity?