Recent content by Skinbleu

This more in-depth technical information only the charger manufacturer has, we buy the charger from a factory in Europe. I will show you some information that I have.

The chargers only rectify the alternating current into direct current to recharge the vehicle's battery. In this process we don't have inductive or capacitive loads.

I said I agree, because I think it's the right thing to do. But the norm here is different, this 25% margin is not considered

I agree that the current must be sized 125% of full load current. We can consider the charger as a purely resistive load, since the power factor is 1. About overcurrent protection, our circuit breakers also work in this mode: thermal and magnetic.

Our charger already comes with DC and AC leakage protection, just needing a breaker to protect the wire.

According to the standards that we follow in Europe, in addition to the circuit breaker, we must have a residual differential switch in the protection, which detects the leakage of current and disarms the circuit, whether due to a bad installation, cable wear or even a person getting a shock. We...

This is the chart for wires made of PVC 750V, we also have wires made of EPR or XLPE 1 kV, but it's in another chart. The letters above refer to installation methods, like cable tray, conduit etc. Sorry for my terrible handwriting, I was translating for you.

To size breakers: Ib<= In <= Iz Where: Ib - circuit current In - breaker current Iz - conductor currentBut it's interesting to understand how the rules are in other countries.

I think it's a case of local regulations. In my country it works the way I explained to you, as you live in another country, there is another type of rule

I understood. It looks like you guys solve the unbalanced circuits in a more complicated way. I was sizing the circuit current first, to size the breakers in the distribution panel.

I'm not a student, this is a serious job, if you want I can introduce my company and our projects

Thank's for the help. This is how I solved it

I'm not a student. If you want, I can introduce you to my company and our projects. The 32 amp it's to provide the 7040W for recharging. Add one more load it's the client request. I already solved the problem but thanks for the help.

I solved it and it was not trigonometry, but thanks for your help

It's not me, it was my client who asked. Anyway thank you for the tip, symmetrical components it's a hard way to solve it, I found a simple way.