For a harmonic oscillator with a restoring force with F= -mω2x, I get that the solution for the x-component happens at x=exp(±iωt). But why is it that you can generalise the solution to x= Ccosωt+Dsin(ωt)? Where does the sine term come from because when I use Euler's formula, the only real part...
oh! I see it now. I got a little confused after calculating the μ (which you rightly pointed out that I used the wrong symbol) ! Thanks so much for the help!
okay so B=1.3367E-5 T
sorry this is my bad. I got μ0=6.28312E-7 instead.
I got this value using IAB=2*1.3367E-5*6.28312E-7=1.7E-11
Should I have used I=0.2A instead?
So I'm having a little trouble getting to the solution to this question so here's my attempt at a solution and I'm not seeing the issue with it
1. I calculated the B-field due to the long wire (approximating the distance from the dipole to be equivalent to that in the centre since r>d)
B=...