I got it from changing the DE into
m^2 + 2m + λ
I did the "m" thing because in the previous chapters to solve some equations I would solve the associated homogeneous DE and use the value of m to determine the structure of the general solution.
It's the only step I have made and I feel like even...
Homework Statement
Find the eigenvalues and the eigenfunctions for
x^2y"+2xy'+λy = 0 y(1) = 0, y(e^2) = 0
Homework Equations
See problem
The Attempt at a Solution
My book has one paragraph on this that does not help me. I tried using an auxiliary equation and solving for lambda...
Homework Statement
Graph the curves y = (x+4)(x-5) and y = ax+2 for various values of a. For what value a is the area between the two curves a minimum?
Homework Equations
y = (x+4)(x-5)
y = ax+2
The Attempt at a Solution
For my attempt I attempted to find the primary equation...
So then using those two values for m I would receive two different values for L. I don't see how having those two lengths solved would help me find the distance to the screen at all. I'm sorry I just don't understand how this leads to a solution...
Homework Statement
Light of wavelength 460nm falls on two slits spaced .3 mm apart. What is the required distance from the slit to a screen if the spacing between the first and second dark fringes is to be 4mm?Homework Equations
dsin(theta)=(m+1/2)lambda
where d = .3mm
y=4mm
lambda = 460nm...