Steve Zissou's latest activity

Thank you Hill.

Thank you to those who have shared their insights here. Let me rephrase one more time...

I'm imagining that the two integrals are Riemann sums in a limit. So I'm seeing the ##f(x,y)##'s all cancelling out as additive terms.

Nope! A trivial counterexample: ##f\left(x,y\right)=e^{-x},\;g\left(x,y\right)=\left(x-1\right)y##. Both of your integrals equal zero...

renormalize, thanks for your reply. In your example, can we not conclude that ##(x-1)y=(x-1)a##?

Thank you all for looking at this. I wish I had a more concrete example but I'm just trying to understand a certain concept here. So...

There's a general mathematical idea that ##A = B## if and only if ##A - B = 0##. You can apply that to your questions. Also, ##g(a)##...

I'm very sorry guys, allow me to make my examples firmer. I don't want to waste your time. I'll be back with a "better question."

I was hoping to be able to make definite integrals here.

Thank you Frabjous. How about this? Let's say we have $$ \int f(x) g(a) dx = \int f(x) g(b) dx $$ ...where a and b are parameters. Can...

let f(x)=1 let g(x)=x integrate from 0 to 1 then a=½ satisfies your relation

Thank you. Is there any chance you can help me understand?

Howdy all, Let's say we have, in general an expression: $$ \int f(x) g(x) dx $$ But in through some machinations, we have, for...

Just for fun - Did Ramanujan actually exist, or was he just an alter-ego of Hardy? What do you think?