Recent content by Sulla

Okay, so I get: I(cm) = 1/12M (L^2 + W ^2) = 1/12M (12^2 + 6^2) = 15M The only other way I can think of to calcualte the speed is: Torque = mg (L/2) = m(9.8)(12/2) T= 58.8M T = I alpha 58.8M/15 = 15M/15 alpha = 3.92 rad/sec^2 Then I used an angular kinematic eq. omega^2 =...

I apologise, I left out the fact that I = 4 kg m^2 .

Assuming that up and right (y) are postive and down and left are negative (x), so the answer would still remain negative. Would that indicate that the object on the left (12 kg) is moving upwards while the object on the right (4 kg) is moving downwards? If the acceleration of both are negative...

There is also another part to this question that I need help with: If the cable snaps, the rectangular mass will rotate about the hinge. Assume the rectangle begins to fall starting from the rest the instant the rope snaps and the moment of inertia about the center of mass, perpedicular to the...

So this portion: T = mg(6) --------- = mg 12(sin 30) becomes mg - T cos 30 ------------- T sin 30 after adding the T cos30 (6)? Wouldn't that change the value of Bx and By though?

I hope this helps!

Determine the tension in the support rope and the forces of the hinge on he uniform rectangular mass below. The length on the rect. is 12 and the height is 6m. The angle that the rope makes with the rectangle is 30 degrees. ____ I broke up the hinge forces into x and y components...

Determine the linear and angular acceleration of the disks. A diagram is illustrated as having a small disk (radius 1m) with a rope hanging on its edge with a mass of 12 kg attached to it. Another pulley disk (radius 2m) surrounds the smaller and first one; it has a rope attached to a 4 kg...