Ok thanks for all your help!
Just to get me back on track, Z is meant to equal Z0 which is: 1/(1x10^(-9)jw + 1/10000)?
I just used the relationships you were describing to find: Y = 1 x 10^(-9)jw + 1/10000
Then to find Impedance: Z = 1/Y, therefore Z = 1/(1x10^(-9)jw + 1/10000)
Is...
Not sure exactly what you meant by your answer to the first two parts.. However the way i calculated it was by simplifying the resistor and capacitor in parallel. This gave me 1x10^4 + 1x10^6/jw. Then I assumed that to remove jw, since Z is now in series with this equivalent resistance, it would...
Exams are coming up and I've been doing some revision from past papers. Having issues with working out part c of the attached problem. I've already calculated part a and b, possibly correct. Basically I simplified resistances and capacitance. And to have a constant frequency I let Z equal the...