Hello all I just need to know if the procedure I'm taking is right.
I need to find energy change of 1.05 Mol of KI(s) given that:
I2(s) → I2(g) : 62.44 KJ/mol
K(s) → K(g) : 180.4 KJ/mol
1/2 I2(g) → I(g) : 138.05 KJ/mol
K+(g) + e− → K(g) ...
Sorry if this question seems like an elementary school topic but I don't really recall anyone really telling me what would happen is an astronaut took off some part of his space suit. I recall that for some reason his blood would boil (?), would he explode(literally) because of no pressure of...
yes I figured that since the height decreases, so does the radius except the problem didn't give me dr/dt or any real mention so I'm not sure how to apply it to the problem if I need to.
Hey guys, I'm having some trouble figuring out this problem and was wondering if someone would be kind enough to look over my work so I know that I am doing it correctly =).
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There is an open right cylinder cone that...
oh ok I get what you're saying now.
Just one last question if anyone can confirm but for part D, I found the zero of teh derivative to be 5.13, I know it's a minimum because the graph changes from negative to positive. So Now I plug that into my original equation like this?: y(x)=2500+Integral...
Ok for Part D I graphed S(t)-R(t). At x=0 y=-2, which doesn't make sense how much sand there is. At x=6 I get y=2.1 and x= 5.1 is a zero. But these values are too small as the original amount of sand is 2500 subic yards. Am I supposed to plug those three values into the original equation of part...
Just a few questions. The integral is S(x)-R(x) and not the other way around? also Hallsof Ivy I think you switched the values of s(t) and r(t) in parts C and D =). Thank you guys are helping me out I kind of knew what to do but just couldn't get it on paper. ^_^
Hey guys, I was doing some practice free response questions for my upcoming AP Calc AB test but was somehwhat unsure of this one.
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Sand is removed from the beach at a certain rate by this function
R(t)=...
for part a, I tried to get the slope from 6-8, which is the derivative and plug in 7 but i am not sure if that;s correct because it came out to be -24.5
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| Distance x in cm | 0 | 1 | 5 | 6 | 8 |
-------------------|-----|----|----|----|----|
| Temp t(x) in °C | 100 | 93 | 70 | 62 | 55 |
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Metal wire is 8 cm. and heated at one end. distance x is how...