Recent content by The Head

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    Chemistry Cleland Diagram & Binding Order from Lineweaver Burke Plots

    I am mostly focused on parts (b) and (d), which I typed out. For (b), I can tell the first pair of graphs is a sequential reaction (when Cysteine is saturated), but it appears ping-pong for the others because the slopes are roughly parallel. I know sequential has to reactants binding (so I...
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    Relating k-values to energy diagrams and rate-determining steps

    I'm trying to understand a little bit more about how k-values relate to rate-determining steps and energy diagrams. I always assumed that the lowest value of k (in the forward direction) was the RDS saw something in a handout that indicated otherwise. It explained that even though k1 > k2...
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    I Clarifying Meaning of a Conditional w/ Quantifiers (∃x)(∀y)(Fyx ⊃ Fyy)

    I've been reading a logic book and saw the logical statement below and have been trying to consider its meaning: (∃x)(∀y) (Fyx ⊃ Fyy) I keep going back and forth whether this statement is implying: a) For all things, if they do F to x, then they do F to themselves -OR- b) If there's some x...
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    Solving a Partial Differential Equation with the Characteristic Method

    Ohh, OK gotcha. So it can just be s^2 * t = u(s,t)? Thanks so much for your reply.
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    Solving a Partial Differential Equation with the Characteristic Method

    Also, I tried u=e^s => s=ln(u), so du/dt = (ln(u))^2, but that gives me an Ei function, so I feel like that can't be correct.
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    Solving a Partial Differential Equation with the Characteristic Method

    dx/dt =1, x(0,s)=0, dy/dt=x, y(0,s) = s, du/dt=(y-1/2x^2)^2, u(0,s)=e^s I did well at the beginning to get x(t,s) =t and y(t,s)=1/2t^2 + s, but got stuck with the du/dt part. You can sub in x=t and y=1/2t^2 +s for x and y to get du/dt = s^2. But that's still three variables, and I can't see...
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    Why Does Second Collision in Ballistic Pendulum Lead to Initial State?

    Ohhh! Yes, of course. If the second ball remained at rest and the first ball went forward, that would make no sense! And after the second collision the signs reverse for the non-zero velocity, so that would also be a contradiction.
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    Why Does Second Collision in Ballistic Pendulum Lead to Initial State?

    Thanks for your reply and that does make sense. Though if they aren't equal, I get a similar equation with two solutions (one equal to zero and one non-zero), but in that case the velocities wouldn't have a clean exchange. The simplest version of non-equal masses would be if the first ball...
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    Why Does Second Collision in Ballistic Pendulum Lead to Initial State?

    I was thinking about ballistic pendulums and the symmetry they exhibit. In the simplest case, you have one ball that begins at a certain height and collides with another ball at rest. You can calculate via conservation of momentum and energy the new velocities and max vertical displacements...
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    I Meaning of Third Eigenvalue in a Tilted Ellipse in a 3x3 Matrix

    I think you'd be right if my vector, x, was (x, y, z), but it's (x, y, 1). I was doing that to account for 2bx and a 2dy terms (whereas the 2 x 2 only has x^2, y^2, and xy terms). Perhaps this step isn't valid, but without my choice of this vector, I don't know how you'd model something like...
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    I Meaning of Third Eigenvalue in a Tilted Ellipse in a 3x3 Matrix

    While reading the Strang textbook on tilted ellipses in the form of ax^2+2bxy +cy^2=1, I got to thinking about ellipses of the form ax^2 + 2bx + 2cxy + 2dy + ey^2=1 and wondered if I could model them through 3x3 symmetric matrices. I think I figured out something that worked for xT A x, where x...
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    First Order Diffy Q Problem with Bernoulli/Integrating Factors

    I seem to be getting an unsolvable integral here (integral calculator says it's an Ei function, which I've never seen). My thought was to use Bernoulli to make it linear and then integrating factors. Is that wrong? The basic idea is below: P(x) 1, Q(x) = 1/2(1-1/x), n=-1, so use v=y^1-...
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    Finding a Unique Solution to a System of Equations

    Hmm, yeah, maybe it was just the wording that is a little ambiguous. It says for a=2 AND b≠-1, the solution is inconsistent (makes sense, because then you get something like 0=1), for a≠2 AND b+4a^2-4a-7≠0, it is unique, and for a=2 AND b=-1 there are infinitely many solutions (also makes...
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    Finding a Unique Solution to a System of Equations

    It makes sense that a=2 would cause problems because then we wouldn't have a matrix of full rank and we'd be unable to determine a value for w. But the key also says that when b+4a^2-4a-7≠0. Why is that an issue? For example, if a=1, that just says implies that w=0. Through back-subsitution...
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