Recent content by TheEyeOfInnos

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    Change of internal energy during linear transformation

    Thanks @Chestermiller! I am able to get the correct answer using this method. However, I am not exactly sure why the reasoning of finding the point up until the system receives heat does not work. @TSny you're right, I meant the adiabatic process being tangent to the linear process. Another way...
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    Change of internal energy during linear transformation

    A linear transformation is described by: $$p=a-bV$$ From that we can find $a$ and $b$: $$b=\frac{p_{2}-p_{1}}{V_{1}-V_{2}} = \frac{2}{9}\frac{p_{1}}{V_{1}}$$ $$a=p_{1}+bV_{1}=\frac{11}{9}p_{1}$$ I considered an adiabatic process that intersects the linear transformation to find the point up...
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