Thanks for the reply. I seem to have got it right then.
With Ia I have
20=3300I_a+6800(I_a-I_c)
-15=6800(I_b-I_a )+2200(I_b-I_c)
15=2200(I_c-I_b )+8200(I_c-I_d)
-25=8200(I_d-I_c )+4700I_d
Cheers.
Homework Statement
Using matrix algebra calculate the voltage expected across each resister in the circuit diagram.
Only need the simultaneous equations.
The Attempt at a Solution
-15=6800(I_b-I_a )+2200(I_b-I_c)
15=2200(I_c-I_b )+8200(I_c-I_d)
-25=8200(I_d-I_c )+4700I_d
Thanks for any help.