Recent content by Tina20

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    Calculating Speed to Reach 1.11 fm from Oxygen Nucleus

    Ok, all is fine :) I double checked everything, I must have missed a digit in one of my numbers the first time! Final answer is 23448253.12 m/s and it is correct! Thank you for all your help Delphi51!
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    Calculating Speed to Reach 1.11 fm from Oxygen Nucleus

    I recalculated by answer and used the protons mass this time. I had a final answer of 2344825.312 m/s which is still wrong. I don't know why the answer is not correct. Everything else that has been inputted into the equations seems logical, I still must be missing something.
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    Calculating Speed to Reach 1.11 fm from Oxygen Nucleus

    Sorry for not including the brackets, I did mean 1/(4*pi*Enot). So I changed the way I approached this question...below is my revised attempt which still ended up being wrong: 1/(4(pi)Enot) * (q oxygen * q proton)/radius min = 1/2 mv^2 9x10^9 (8*1.602x10^-19 *...
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    Work function of a cathode, when the wavelength of light is increased by 50%

    Nevermind! I made a mathematical error. I solved the question and got the right answer! Thank you so much! I posted another post in regards to a proton being fired towards on Oxygen nucleus and I need to find the velocity at which the proton needs to be fired towards the oxygen nucleus. I...
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    Work function of a cathode, when the wavelength of light is increased by 50%

    So I solved for lambda and got an answer of 3,265962.795 m for lambda I substituted that into the equation: E2 = hc/1.5 lambda - W I got an answer of 1.776x10^-19 J for -W. I inputted with positive value of the answer into the computer and it says the answer is wrong. Is my answer...
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    Work function of a cathode, when the wavelength of light is increased by 50%

    Ok, thank you for your help, I will work on it right now :)
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    Work function of a cathode, when the wavelength of light is increased by 50%

    So i thought of converting the equation I posted below to: Kmax = hc/lambda - hc/lambda not because hf = hc/lambda So if Kmax = -2.03 and h*c = 1.989x10^-25 Then the equation would be as follows: -2.03 eV = 1.989x10^-25/lambda - 1.989x10^-25/lambda not now in the question it...
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    Work function of a cathode, when the wavelength of light is increased by 50%

    Homework Statement The maximum kinetic energy of photoelectrons is 3.14 eV. When the wavelength of the light is increased by 50.0 %, the maximum energy decreases to 1.11 eV. What is the work function of the cathode? Homework Equations Kmax = E elec - E not = hf - hfnot hf =...
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    Calculating Speed to Reach 1.11 fm from Oxygen Nucleus

    Homework Statement The oxygen nucleus 16O has a radius of 2.91 fm. With what speed must a proton be fired toward an oxygen nucleus to have a turning point 1.11 fm from the surface? Homework Equations Kinetic energy = 1/2 mv^2 Potential energy = 1/4(pi)Enot * q/radius min The...
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    Electric Potential at point where Electric Field is Zero

    Ok, I am still not understanding what I am doing wrong and why my answer is not right. I have tried with positive and negative values of the square root and still the answer is incorrect. Can someone please help to show me where exactly I am going wrong?
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    Mass Spec Problem Accelerating potential difference ΔV is required to detect N2+?

    Homework Statement The image below shows a mass spectrometer, an analytical instrument used to identify the various molecules in a sample by measuring their charge-to-mass ratio e/m. The sample is ionized, the positive ions are accelerated (starting from rest) through a potential difference...
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    Electric Potential at point where Electric Field is Zero

    Homework Statement a) A -10.1 nC point charge and a +18.9 nC point charge are 13.8 cm apart on the x-axis. What is the electric potential at the point on the x-axis where the electric field is zero? b) What is the magnitude of the electric field at the two points on the x-axis where the...
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    Electric Charge and Electric Field Problem

    Can someone please help with this question :) I am confused as to what to do as well :( Tina
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    Solve Electric Field for (x,y) Position

    It worked, thank you so much for your help! just in time too, deadline is midnight :)
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    Solve Electric Field for (x,y) Position

    So since the charge is negative, the field points towards the negative charge, so my x position is actually 0.0350m + 0.00695m
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