Okay that's really clever... it's taken me a while to figure out how that works.
So, if I have 0 \leq x < 2\pi, I think taking the arcsin would give:\alpha+2x=\frac{3\pi}{2}Then, given how we've defined \alpha, I feel like we can say:\tan\alpha = \frac{(B-A)}{2C}Putting those things together, I...