I'm not sure what you mean by this, would the line still be curved concave up from t = 0 s to t = 20 s? My rationale for this is that there is an increasing force being applied to the object so it would experience an increasing acceleration and therefore a velocity increasing over time.
Would...
Thanks for the response. Looking at part a again with the formula provided, the mass would be 36 kg (not 34 kg, which was a calculation error :doh:)
mv = J
m(1.5) = 54
m = 36 kg
Knowing this, we could then find the velocity at t = 20 s by evaluating the impulse at 20 s.
mv = ∫0 to 20 of F(t)...
(bottom graph relates only to c)
(a)
i. The students can calculate the area under the graph to find the impulse exerted on the block. This is because the area under a force vs. time graph is the change in momentum or the impulse.
ii. Knowing that the graph is linear and begins at around 3 N...