Recent content by ydydry

  1. Y

    Series with binomial coefficients

    I apologize for the last attempt to write the code in Latex. I am not familiar with the software, and I clearly failed. I enclose a picture of the expression, which should be more readable than the non-sense above code
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    Series with binomial coefficients

    \overset{n}{\underset{s=0}{\sum }}\left( \frac{pq}{(1-p)(1-q)}\right) ^{s}\left( \begin{array}{c}n \\ s% \end{array}% \right) \left[ \left( \begin{array}{c}m-1 \\ s% \end{array}% \right) (pq(m+n)+(2m-1)(1-p-q))\right] =\overset{n}{\underset{s=0}{\sum }}% \left( \frac{pq}{(1-p)(1-q)}\right)...
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    Series with binomial coefficients

    Hi all, I have an apparently simple equation. I copy here its Mathematica code: Sum[(p/(1 - p))^s*(q/(1 - q))^s*Binomial[n, s]*(Binomial[m - 1, s]*(p*q*(m + n) + (2*m - 1)*(-p - q + 1))), {s, 0, n}] == Sum[(p/(1 - p))^s*(q/(1 - q))^s*Binomial[n, s]*((-(-p - q + 1))*Binomial[m - 2, s] +...
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    System of cross-polynomials of variable degree

    Dear all, I am stuck with an apparently easy system of 3 simultaneous equations that has to be solved in x,y and z. The system is the following: ##(y+z) / ((x+y+z)²)=ax^{α-1}## ##(x+z) / ((x+y+z)²)=by^{α-1}## ##(x+y) / ((x+y+z)²)=cz^{α-1}## The parameters (a,b,c) and the variables (x,y,z) are...
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