Recent content by yeahyeah<3

okay. thanks so much again!

so it is E 30! 15! Thanks so much! just one last question.. I don't understand how you got \frac{f^{(30)}(3)}{30!}(x-3)^{30} only because I thought that it would be the 30th derivative of f(3) not f^30 (3)

i still don't understand =/I know the bottom of the term is 15! but I don't know how to get what the top is...

I'm not sure what you mean..? like f'(30) (x-3)^30 kind of thing? 30!

how do you get the math problem to look like that -.- and that is the question I'm asking for help on... i think the term looks like (x-3)^30 15! ? but how does that answer the question? Thanks!

Homework Statement The Taylor polynomial of degree 100 for the function f about x=3 is given by p(x)= (x-3)^2 - (x-3)^4/2! +... + (-1)^n+1 [(x-3)^n2]/n! +... - (x-3)^100/50! What is the value of f^30 (3)? D) 1/15! or E)30!/15! Homework Equations The Attempt at a...

n --> infinity and my teacher has us include our x term you sub in n+1 for all n and then multiple by the 1/an

(2n+3) (x-2)^n+1 (3n-1) (x-2)^n (3n+2) times (2n+1) with a limit in front of that.. isn't that 6/6 = 1?

Ratio Test for Absolute Convergence. Basically to find the values of x for which the series converges. when the test is applied the limit turns out to be one i believe... =/

3/2 which makes sense but.. the limit is 1 when the R.T.A.C is applied?

Limit = (2/3) ? However, according to the answer key the answer is (3/2). I'm just looking for how to get that answer.

while that is true, that is not a choice. A) 0 B) 2/3 C) 3/2 D) 2 E) infinite

Homework Statement The coefficients of the power series the sum from n=0 to infinity of an (x-2)^n satisfy ao=5 and an= [(2n+1)/(3n-1)] an-1 for all n is greater than or equal to 1. The radius of convergence of the series is A) 0 B) 2/3 C) 3/2 D) 2 E) infinite Homework Equations...

I apologize for those mistakes. However, I am still confused in what you are saying to do. Tan (pi/2) is undefined. I'm not sure how to get the slope. I know the slope is the derivative or dy/dtheta/dx/dtheta but I don't know how that helps me. Thanks!

Homework Statement What is the slope of the line tangent to the polar curve r=2theta at the point theta= pie/2 Homework Equations r = xcos theta r= ysin theta The Attempt at a Solution I kept getting zero but the answer is -2/pie. Can anyone give me a hint? :) Thanks!