When the trolley moves down, the following expression gives you the acceleration
a = g \sin \theta , where \theta is the angle of inclination
So, what can you say about the magnitude of the acceleration if you increase the mass?
But I think if you are striving to become a Pharmacist, look at the suject areas to which you should focus first rather than looking at which subject you are good at.
______________________________________________________
AKG
"Nothing is impossible in life, however difficult it may seem"
What are you trying to do KingAS for your project? Are you going to investigate on an experiment or are you trying to devise something(a particular device)?
_________________________________________________________________
A
The theoretical value should be 68.75 Ohms ! And that's the "calculated" value. So, your actual value is 68 Ohms, which is consistent with any real value!
You should expect your values to be less than the theoretical values because of various reasons: -
1. Energy loss due to resistance of...
For the first one, try using the Principles of Conservation of Momentum (do you know anything about this law? if yes, that part should be really easy! )
For the second one, I assume that the ball moves in a vertical direction upwards.
You are given the average force exerted by the spring on...
as vincentchan suggested, friction = \mu R, you can get the frictional force by using Friction = m a where a is the magnitude of the deceleration. There are no other horizontal forces being applied, so, you can easily evaluate for \mu
Draw a diagram of th situation. Draw the forces acting on the crate. in this case, since it's moving at constant speed, there is no acceleration.
since the rope is at 33 degrees, it would be a right angled triangle with the adjacent of the 33-degree angle being of magnitude 809
from...