in chem. class asked the question nd he ignored me, i hope smeone here can help me? wht are the properties of electrolytes nd how do yu kno they coduct electcity nd also how ud yu determinet lowest freezing eezing poin
hmm okay i understand.
i tried that and this was my process/answer:
i cross mult - n!(n-3)!=8n!(n-4)
i then divided (as you suggested) n!(n-3)!/8n! = 8n!(n-4)!/8n!
i then tried to isolate the N by adding the 4 onto the other side giving me (n+1)!/8 = n!
I tried solving like a normal...
yeah, this is the stage I am talking about, exactly what am i suppose to do to simplify.
im thinking to cross mult. b/c its a proportion and turn it into a quad form? the problem is, the factorials; how can I simplify with all of them? and there are no factorials for N! (that I can solve out)...
Homework Statement
the problem states solve for n.
nP4 = 8(nP4)
Homework Equations
no relevant equat. i can think of?
The Attempt at a Solution
my attempt at this was nP4 = 8(nP3)
idk what i tried to do, but i tried to get it in standard form i guess: n!/ (n-4) = 8(n!)/(n-3)
it...