How many lines per centimeter does the grating have?

AI Thread Summary
The discussion revolves around calculating the number of lines per centimeter on a diffraction grating given a wavelength of 488 nm and a second-order bright fringe at an angle of 8.02°. The equation used is d sin q = nl, where d is the grating spacing, n is the order of the fringe, and l is the wavelength. The initial calculation for d resulted in an incorrect value due to improper unit conversion of the wavelength. It is suggested to convert the wavelength from nanometers to meters or centimeters to achieve the correct result. Proper unit conversion is essential for accurate calculations in diffraction grating problems.
George_H
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Homework Statement



The light shining on a diffraction grating has a wavelength of 488 nm (in vacuum). The grating produces a second-order bright fringe whose position is defined by an angle of 8.02°. How many lines per centimeter does the grating have?


Homework Equations



d sin q = nl

The Attempt at a Solution



d = (2)(488)/sin(8.02) = 6995.474955

d = 1/N

N = 1/d = 1/6995.474955 =1.429495505X10^-4 (per M) X 100 = 0.014294955

It got this answer and it is wrong, I have no idea where to go from here or what to do and would be grateful of any help, thanks!
 
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You should convert the wavelength from nanometers to meters (or cm, whatever). I don't think you did that properly.
 
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