Is 0 Odd or Even in Mathematics?

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Zero is classified as an even number because it is divisible by two without a remainder. In the context of functions, the definitions of even and odd functions are crucial; an even function satisfies f(-x) = f(x), while an odd function satisfies f(-x) = -f(x). The constant function f(x) = 0 is both even and odd, as it meets the criteria for both definitions. The hyperbolic cosine function, cosh(x), is already an even function, while the hyperbolic sine function, sinh(x), is odd. Overall, the discussion clarifies that while zero is even, it also highlights the nature of constant functions in relation to evenness and oddness.
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Is 0 an odd or even number? The reason why I ask is this:

I need to write cosh(x) as the sum of an even and odd function. I could only come up with cosh(x) = cosh(x) + 0, where cosh(x) would be the even and 0odd. However, this doesn't make any sense since 0 is exactly divisible by 2 with no remainder, hence it is even. So which one is it?
 
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0 is an even number.But that has nothing to do with writing cosh as a sum of odd and even *functions*.
 
The definition of an "even" function is that f(-x)= f(x). The definition of "odd" function is f(-x)= -f(x). If f(x)= 0 for all x then f(-x)= 0= -0= -f(x) but also f(-x)= 0= f(x) so f(x)= 0, the constant function, is both even and odd.
However, as matt grime said, that has nothing to do with the fact that 0 = 2(0) is an even number.

cosh(x) is already an even function. sinh(x) is an odd function. In fact,
ex= cosh(x)+ sinh(x). cosh(x) and sinh(x) are the even and odd "parts" of ex.
 
0 mod 2 = 0, it means that 0 is even :rolleyes:
 
In general, given a function f, you can write it as the sum of an even function and an odd function as follows:

f_{even}(x) = (f(x) + f(-x))/2
f_{odd}(x) = (f(x) - f(-x))/2
 
what about 6? is it odd or even?
 
Okay, I'll bite: even?


Actually, a more interesting question would be whether 5 is odd or even.

The number 5 is obviously odd.

The constant function (which is what this thread is really about), f(x)= 5, is even.
 
good point, so the answer to the OPs question is "yes".

i.e. all constant functions are even and one of them is also odd.
 

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