How do I calculate the elastic potential energy stored in a spring?

AI Thread Summary
To calculate the elastic potential energy stored in a spring, use the formula PE = (1/2)kx², where k is the spring constant and x is the displacement from the spring's relaxed length. In this case, the spring's relaxed length is 0.115 m, and its length when compressed is 0.145 m, resulting in a displacement of 0.030 m. Substituting the values into the formula gives PE = (1/2)(45.0 N/m)(0.030 m)². The discussion clarifies that understanding the relationship between force and potential energy is essential, especially for those familiar with calculus. The final calculation yields the elastic potential energy stored in the spring.
lilmul123
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This is my first time here! Thanks for the help in advance.

The staples inside a stapler are kept in place
by a spring with a relaxed length of 0.115 m.
If the spring constant is 45.0 N/m, how
much elastic potential energy is stored in the
spring when its length is 0.145 m? Answer in
units of J.

I know I have to use F=kx (maybe), but what's confusing me is the potential energy part. How do I fit that into finding the answer?
 
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elastic P.E = work done to compress =integral of [(F)x(dx)] between the limits 0.145 and 0.115
 
If you haven't done calculus, the result Amith2006 is pointing you toward can be written PE=(1/2)*k*x^2, where x is the displacement from equilibrium.
 
Yeah, I've done calculus, but thank you both!
 
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