Limits of Average Rates of Change

Alyosha
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I'm not looking for an answer to a specific question, but I want to know in general how to evaluate the limit of average rates of change.

Homework Statement



lim_{}h \rightarrow0 f (x + h) - f (x) / h


Homework Equations



f(x) = x^2 , x = 1



The Attempt at a Solution



I really don't know what to do. Obviously we need the denominator not equal to 0. An example in my book showed them multiply by 1 by multiplying the numerator and denominator by the conjugate since the numerator had roots...but this has no roots.
 
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I don't want to do your homework, so I'll do f(x) = x^3.
\lim_{h\rightarrow 0} \frac{f(x+h)-f(x)}{h}

\lim_{h\rightarrow 0} \frac{(x+h)^3-x^3}{h}

\lim_{h\rightarrow 0} \frac{x^3 + 3x^2h + 3xh^2 + h^3 - x^3}{h}

\lim_{h\rightarrow 0} \frac{3x^2h + 3xh^2 + h^3}{h}

\lim_{h\rightarrow 0} 3x^2 + 3xh + h^2

=3x^2
 
If it says for example x = 1, all you do f (1) and evaluate?
 
Right, so in the example I did, f ' (1) = 3, f ' (2) = 12 etc.
 
Well Since you know that you must evaluate at x=1, you can do two things. Either do as nicksauce did, and sub in x=1 at the end, or simply evaluate

\lim_{h\to 0} \frac{(1+h)^2 - 1^2}{h} Directly.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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