What Is the Spring Constant of the Second Spring in a Dual-Support System?

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To determine the spring constant of the second spring in a dual-support system, the gravitational force acting on the ball must be calculated, which is equal to the weight of the ball (mass times gravity). The force exerted by the first spring can be found by multiplying its spring constant (475 N/m) by its displacement (0.35 m). The force exerted by the second spring can then be derived by subtracting the force from the first spring from the total gravitational force. Finally, the spring constant of the second spring is calculated by dividing the force it exerts by its displacement at equilibrium. This method allows for the accurate determination of the second spring's constant based on the system's equilibrium conditions.
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Homework Statement


A 7.50-kg ball is placed on top of a spring with a spring constant of 475 N/m that has an initial length of 35.0 cm (h1). When the ball has reached its equilibrium position, it is supported by both springs at a height of 20.0 cm above the table (h3). If the shorter spring has an initial length of 25.0 cm, what is its spring constant?


Homework Equations


f=kx ---->attached is the makeshift drawing i made to resemble the actual diagram since it was to big.


The Attempt at a Solution


this is what my teacher has told me to do : The magnitude of the force exerted by the second spring is equal to the gravitational force minus the force the first spring exerts on the mass. Divide the force the second spring exerts on the mass by the displacement of that spring when the ball is at equilibrium position to find the spring constant for the second spring.

so i have to find the force of both springs whcih i can do for the first one by multiplying 475n/m by 0.35m. how do i find the force of the second one tho?
 
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sorry. here is the diagram
 

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