Electrical Voltage, a appliance problem

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The discussion revolves around calculating the power factor and supply voltage of a 240V, 50 Hz appliance rated at 2 kW with a lagging power factor of 0.7 when operated at 60 Hz. To find the new power factor at 60 Hz, the impedance of the load must first be determined using the equation P=V^2/Z, followed by calculating the reactance, which is frequency-dependent for inductive loads. The relationship between reactance at different frequencies is highlighted, emphasizing that reactance increases proportionately with frequency. The power factor can then be recalculated using the new reactance while keeping resistance constant. This approach provides a systematic method for solving the problem at hand.
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Homework Statement



Anyway can you please help me out with the following?

240V , 50 Hz electrical appliance is rated at 2 kW. It has a lagging power factor of 0.7
(a) What is appliances power factor when it is used on a 60Hz supply.
(b) What is supply voltage required to maintain appliance at its rated power when operated off a 60 Hz supply?


2. The attempt at a solution
No idea..!

Can you suggest some relevant equations and guidance?
Thanks in advance
 
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First find Z of the load using the relation P=V^2/Z. Then using the given power factor you can find the reactance X=Zsin(theta). Let this be X1. Now find new X (X2) for 60 Hz. Remember X is directly proportional to frequency for a lagging circuit since it is inductive. From X2 you can calculate the parameters you want to know.
 
Hello, can you be bit more explanatory?
i am not getting anything !
 
You are asked to find pf on 60 Hz. You may remember that the impedance of the load Z=R+jX, where X is positive for inductive loads i.e., lagging pf and only X is dependent on frequency. Also pf=tan(X/R). Now if you change frequency of supply X changes proportionately. You know X=2*pi*f*L for inductive load. So for change in frequency from f1=50Hz to f2=60Hz , we have X2/X1=f2/f1. The first thing you have to do is find X1 i.e., X at 50 Hz using relations I mentioned earlier (Note pf=cos(theta) and so you can find theta). Then find X2 and from this since R is unchanged, you can find new pf.
 
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