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jehan60188 is offline
Feb19-12, 11:00 AM
P: 204
let's say a fridge uses 200 KwH of power (a very generous rounding)

one joule/second = 1 watt
1000*60*60 j/s = 1 kwh
a 200 kwH fridge needs 1000*200 kw every hour. that's 1000*200/(60^2) = 55 joules/second
let's say an out-of-shape cyclist can generate 200 watts
that's 200 joules/second

you'd have to ride 6 hours/day to run the fridge (assuming you have a flywheel, or battery, or something harnessing the spare energy)
i guess 3 hours in the morning, and 3 hours before bed seem feasible
it'll probably be closer to 8 hours/day