A Question About Weight and Pressure

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The discussion focuses on the relationship between weight and pressure in three different liquid-filled shapes. Sample A shows that weight equals pressure, while Sample B indicates that weight is less than pressure, and Sample C shows weight greater than pressure. The extra pressure in Sample B is attributed to the slanted walls exerting a downward force, while in Sample C, the slanted walls exert an upward force. It is clarified that weight is a force acting downward, whereas pressure is a force per unit area acting in all directions. The conversation highlights the need for a deeper understanding of these concepts, as the initial explanations may not satisfy advanced inquiries.
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Hello there :) First I'm sorry for my English it might be kinda bad !

I Have a little question about Weight and Pressure, Hope this is the right place.

1qh501.jpg


Here in this image we have 3 samples, A, B and C.

They are 3 different types of shapes fulled with a liquid (let's say water)

Talking about the physical pressure on the bottom of every shape :-

In Sample (A) we can see that Weight = Pressure.
In Sample (B) we can see that Weight < Pressure.
In Sample (C) we can see that Weight > Pressure.

Where did we get the extra pressure in the sample (B) ? It's like we create that green area from nowhere!
And where did the extra weight go in the sample (C) ? It's like we lost that orange area and it's nothing!

Hope I can fine the answer, Thank you :) !
 
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MBrain said:
In Sample (A) we can see that Weight = Pressure.
In Sample (B) we can see that Weight < Pressure.
In Sample (C) we can see that Weight > Pressure.
Where you say "weight", I assume you mean "weight/area". (Which would give you a pressure term.)
Where did we get the extra pressure in the sample (B) ? It's like we create that green area from nowhere.
The slanted walls exert a downward force.
And where did the extra weight go in the sample (C) ? It's like we lost that orange area, or it is nothing!
Here the slanted walls exert an upward force.
 
Weight and pressure are very different things. For starters, weight is a force and has units of Newtons. Pressure is a force per unit area and has units of N/m². Weight only acts downward toward the center of the Earth. Pressure acts in all directions simultaneously.

Pressure is not like light intensity (energy/m²), either. If you increase the area on the bottom, the pressure at the bottom is spread over a larger area but it is not thereby diminished as light intensity would be if spread over a larger area. Consider a balloon. If you blow it up to a pressure of 1.1 atmospheres, then pump it up to 1.2 the balloon gets larger and the pressure is 1.2 on every bit of the larger surface area.
 
Doc Al said:
Where you say "weight", I assume you mean "weight/area". (Which would give you a pressure term.)

The slanted walls exert a downward force.

Here the slanted walls exert an upward force.

And where that forces come from ?!
 
MBrain said:
And where that forces come from ?!
The pressure of the water against the containing walls. Which, as pointed out by Delphi51, acts the same in all directions.
 
Doc Al and Delphi51 Thank you for your helping.
but when I explained it that way to my teacher he said that its not exactly the right answer.
I think he is looking for a really advance answer that explains it all.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

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