Engineering Trying to explain how a Relaxation Oscillator UJT circuit works

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A Relaxation Oscillator circuit using a Uni-Junction Transistor (UJT) operates by utilizing the UJT's unique characteristics, including its single emitter and two bases. The UJT remains off until the emitter voltage reaches the peak voltage (Vp), at which point it conducts and allows current to flow through B1. The relation coefficient η, defined as Rb1/(Rb1+Rb2), influences the timing of the oscillation. As the capacitor charges and reaches Vp, it triggers the UJT, generating pulses until the voltage drops to a minimal value (Uv), returning the UJT to cutoff. This circuit effectively produces a repetitive output of voltage pulses.
Femme_physics
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http://img689.imageshack.us/img689/7084/ujte.jpg This is a Relaxation Oscillator circuit with UJT. I need to A) Explain what is UJT, explain its relation ratio of η for the UJT, and explain what Vp is. And in B) Explain how does the circuit work, and what is the output (or turnout) of the circuit

Trying to use my own wordsUJT is a uni-junction transistor that has a single emitter and two bases. As long as the voltage in the emitter is smaller than the breakthrough voltage (Vp) , the UJT acts as disconnection.
When the voltage in the emitter gets to the same voltage as Vp, the resistance at the base is broken through B1, and when the voltage in the emitter drops to a minimal value Uv, UJT is back to cutoff.

relation coeffcient - η = Rb1/(Rb1+Rb2)

Vp is "peak voltage" or "breakout" voltage. When the voltage in the emitter arrives to Vp then the UJT opens up (broken though).

(Hope I didn't lose anyone by now!)

B) This circuit generates pulses. Its made out of UJT and a capacitor. The capacitor is loaded from the source and when it reaches Vp, the UJT opens up and current flows from the Emitter through B1.
 
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Well, I haven't learned about UJT's before, but after googling it I'm drawing the conclusion that you summed it up nicely. :)
Actually, I like your explanation better than some others on the internet.

I'm turning into an electronics expert thanks to you!
 
Much appreciated :)
 
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