How exactly do you find the net force between charges?

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To find the net force between charges, the formula k*q1*q2/r^2 applies, with the force direction being opposite for like charges. When two protons are involved, the forces cancel each other out, resulting in a net force of zero if they are equidistant. Introducing a third electron can also maintain a net force of zero, as the forces between the particles remain equal and opposite. The net force on each particle is the sum of the forces exerted by the others, leading to a balanced system. Understanding these principles is crucial for solving problems related to electrical forces.
paki123
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I was doing some homework problems, and I came across a couple I didn't know. I then realized I must have screwed up my understanding on electrical forces.


For an electrical force, if there are two protons, the force is k*q1*q2/r^2. The direction is in the opposite direction.

<---(+) (+)--->


Right?

What would be the net force there assuming the charge is e? Would it be 0 since they are in the opposite direction and have equal distances?

My question is it possible to have a third electron and still have the net force equal to 0?
 
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Yes and Yes! If \textbf{F}_{i, j} means the force that charged particle j exerts on charged particle i, then \textbf{F}_{i, j} = \textbf{F}_{j, i}. In other words the forces between the particles are equal and opposite.

For three particles,
the force on particle 1 is \textbf{F}_{1, 2} + \textbf{F}_{1, 3}
the force on particle 2 is \textbf{F}_{2, 3} + \textbf{F}_{2, 1}
the force on particle 3 is \textbf{F}_{3, 1} + \textbf{F}_{3, 2}

So the net force, that is the forces on all three particles added together, is zero, because
\textbf{F}_{1, 2} = -\textbf{F}_{2, 1} and so on.
 
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