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Nov5-03, 05:45 PM
then if an odd perfect number existed it will be of the form: ?(n)=2n+1
No... if n is an odd perfect number, it is still the case that σ(n) = 2n.
If σ(n) = 2n + 1, that would mean the sum of all the positive divisors of n (not including n) would be n + 1.