Circluar Motion Involving Rotations Per Minute


by fishyfish
Tags: acceleration, circular motion, uniform, velocity
fishyfish
fishyfish is offline
#1
Jan7-09, 08:32 PM
P: 1
1. The problem statement, all variables and given/known data

What is the magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 40 rpm (revolutions per minute) if the wheel's diameter is 35 cm?

2. Relevant equations

v=2(pi)(r)/t a=(v^2)/r

3. The attempt at a solution

2(3.14)(.175)/.67 = 1.099

(1.099^2)/.175=a
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LowlyPion
LowlyPion is offline
#2
Jan7-09, 09:03 PM
HW Helper
P: 5,346
Welcome to PF.

Isn't your period 1.5 instead of .67?

You only get 40 revs per min so a rev should be longer than a sec no?


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