Circluar Motion Involving Rotations Per Minuteby fishyfish Tags: acceleration, circular motion, uniform, velocity 

#1
Jan709, 08:32 PM

P: 1

1. The problem statement, all variables and given/known data
What is the magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 40 rpm (revolutions per minute) if the wheel's diameter is 35 cm? 2. Relevant equations v=2(pi)(r)/t a=(v^2)/r 3. The attempt at a solution 2(3.14)(.175)/.67 = 1.099 (1.099^2)/.175=a 



#2
Jan709, 09:03 PM

HW Helper
P: 5,346

Welcome to PF.
Isn't your period 1.5 instead of .67? You only get 40 revs per min so a rev should be longer than a sec no? 


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