Circluar Motion Involving Rotations Per Minute

AI Thread Summary
To calculate the acceleration of a speck of clay on a potter's wheel turning at 40 rpm with a diameter of 35 cm, the relevant equations for linear velocity and centripetal acceleration are used. The radius is derived from the diameter, leading to a calculation of velocity. There is a correction noted regarding the period of rotation, suggesting it should be 1.5 seconds instead of 0.67 seconds, as each revolution takes longer than a second given the 40 rpm rate. This discrepancy impacts the final calculation of acceleration. Accurate understanding of the period is crucial for determining the correct magnitude of acceleration.
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Homework Statement



What is the magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 40 rpm (revolutions per minute) if the wheel's diameter is 35 cm?

Homework Equations



v=2(pi)(r)/t a=(v^2)/r

The Attempt at a Solution



2(3.14)(.175)/.67 = 1.099

(1.099^2)/.175=a
 
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Welcome to PF.

Isn't your period 1.5 instead of .67?

You only get 40 revs per min so a rev should be longer than a sec no?
 
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