- #1
james.farrow
- 44
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Integrating factor!
As promised I'm back with integrating factor differential equation.(x^2 + 1)dy/dx -2xy = 2x(x^2+1) y(0)=1
First put into standard from by dividing thru by (x^2 +1 )dy/dx -2xy/(x^2 + 1) = 2x
Integrating factor is given by exp( integral of -2x(x^2 + 1))
After some working out I get the IF to be 1/(x^2 + 1)
Now the solution is given by
y(x)=1/IF(integral of 2x(x^2 + 1)
Hopefully I'm on the right track so far...
After doing the integration by parts and some tidying up I have
y(x)= (x^2 + 1){(2(x^2 + 1)x^3)/3 - 4x^5/15} + C
After plugging in the values I have 1=C
What do you think??
As promised I'm back with integrating factor differential equation.(x^2 + 1)dy/dx -2xy = 2x(x^2+1) y(0)=1
First put into standard from by dividing thru by (x^2 +1 )dy/dx -2xy/(x^2 + 1) = 2x
Integrating factor is given by exp( integral of -2x(x^2 + 1))
After some working out I get the IF to be 1/(x^2 + 1)
Now the solution is given by
y(x)=1/IF(integral of 2x(x^2 + 1)
Hopefully I'm on the right track so far...
After doing the integration by parts and some tidying up I have
y(x)= (x^2 + 1){(2(x^2 + 1)x^3)/3 - 4x^5/15} + C
After plugging in the values I have 1=C
What do you think??