Nov8-10, 06:43 PM
1. The problem statement, all variables and given/known data
A cow, with a mass of 327 kg, if fired from a medieval catapault, and travels a horizontal distance of 1375 m. It lands in a depression 39 m below its starting position. If it is launched at an angle of 37.0above the horizontal, find its initial speed.
dy= -39 m
2. Relevant equations
x = x_0 + v_0 t + (1/2) a t^2
3. The attempt at a solution
What I did here was make a equation for time of flight for the horizontal
dx=v1*cos37* t +1/2 at^2
I then entered this into my vertical distance
dy=v1y*cos37* t +1/2 at^2
-39=v1*sin37*(1372/v1*cos37) + 1/2 (-9.81)(1372/v1*cos37)^2
Now this equation is where it gets tricky, I am not sure how to solve for v1.
Nov8-10, 07:40 PM
at that point you should plug in to get rid of sin and cos so you are working with decimals and just follow order of operations. if you have a graphing calculator it would make life much easier but if not just plug and chug and go step by step as to not lose anything.
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