- #1
DeerHunter
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Homework Statement
A cow, with a mass of 327 kg, if fired from a medieval catapault, and travels a horizontal distance of 1375 m. It lands in a depression 39 m below its starting position. If it is launched at an angle of 37.0above the horizontal, find its initial speed.
Givens
HOR
dx= 1375
V1x= ?
ax= 0m/s2
v2x=v1x
VER
dy= -39 m
v1y= ?
ay= -9.81m/s2
v2y=?
T=?
Homework Equations
[tex]
x = x_0 + v_0 t + (1/2) a t^2
[/tex]
The Attempt at a Solution
What I did here was make a equation for time of flight for the horizontal
dx=v1*cos37* t +1/2 at^2
1375=v1x*cos37*t
t= 1372/v1*cos37
I then entered this into my vertical distance
dy=v1y*cos37* t +1/2 at^2
-39=v1*sin37*(1372/v1*cos37) + 1/2 (-9.81)(1372/v1*cos37)^2
Now this equation is where it gets tricky, I am not sure how to solve for v1.